Deepseek R1
vs
GPT o1-preview

o1-preview output

Deepseek R1 output

There are **2** instances of the letter 'r' in "strawbery."

The word "strawbery" contains the letter 'r' **2 times**.

o1-preview output

Deepseek R1 output

B

A

o1-preview output

Deepseek R1 output

Life is a journey, a winding road,
A dance of moments, stories untold.
Echoes of laughter, shadows of tears,
Weaving together the days and the years.

Sunrise to sunset, paths intertwine,
Hearts find direction, souls seek a sign.
Through trials and triumphs, joy and strife,
We wander, we wonder—this mosaic is life.

A thread of dawn, a twilight sigh,  
The breath between a blink and sky—  
A dance of shadows, fleeting, warm,  
A tempest woven into form.  

We trace our maps in rivers’ veins,  
Through valleys carved by joy and pains,  
Each scar a star, each loss a tune,  
In chaos, life begins to bloom.  

The seasons turn, yet roots dig deep,  
Where storms and quiet cradle sleep.  
A firefly’s flicker, brief, unplanned—  
The universe cupped in a hand.  

So tread the edge where mysteries pour,  
For grace exists in what’s unsure.  
A heartbeat’s hum, the dark, the dawn—  
This borrowed light goes on… goes on.

o1-preview output

Deepseek R1 output

Here are the possible valid ways to parenthesize 
the expression and their corresponding values:

1. **Original expression**:
   \((2 \cdot 3 \cdot 4 \cdot 5) + 1 = 121\)

...

5. **Grouping \(2 + 3\) first**:
   \(((2 + 3) \cdot 4 \cdot 5) + 1 = 101\)

...

So, there are **7 different values** obtainable.

\(\boxed{7}\)

Deepseek R1 output
...

3. **Adding 1 to the product of the last two terms (4 and 5)**:
   \[
   (2 \cdot 3) \cdot (4 \cdot 5 + 1) = 6 \cdot 21 = 126
   \]
   This can also be grouped in different ways, but the result remains 126.

4. **Adding 1 to the product of the last three terms (3, 4, and 5)**:
   \[
   2 \cdot (3 \cdot 4 \cdot 5 + 1) = 2 \cdot 61 = 122
   \]

By systematically analyzing all possible ways to insert parentheses, 
we find that the different values obtained are 121, 144, 126, and 122. 
Each of these values corresponds to adding 1 at different stages 
of the multiplication process. 

Thus, the total number of distinct values that can be obtained is \(\boxed{4}\).

o1-preview output

Deepseek R1 output

def findMedianSortedArrays(nums1, nums2):
    m, n = len(nums1), len(nums2)
    
    # Ensure nums1 is the smaller array to minimize the binary search range
    if m > n:
        nums1, nums2, m, n = nums2, nums1, n, m

    # Handle the case where both arrays are empty
    if n == 0:
        raise ValueError("Both arrays are empty.")

    imin, imax = 0, m
    half_len = (m + n + 1) // 2

    while imin <= imax:
        i = (imin + imax) // 2  # Partition index for nums1
        j = half_len - i        # Partition index for nums2

        # Edge cases where partition is at the extreme ends
        maxLeftX = nums1[i - 1] if i > 0 else float('-inf')
        minRightX = nums1[i] if i < m else float('inf')

        maxLeftY = nums2[j - 1] if j > 0 else float('-inf')
        minRightY = nums2[j] if j < n else float('inf')

        # Check if we have found the correct partition
        if maxLeftX <= minRightY and maxLeftY <= minRightX:
            # Compute the median based on the total length parity
            if (m + n) % 2 == 0:
                return (max(maxLeftX, maxLeftY) + min(minRightX, minRightY)) / 2.0
            else:
                return max(maxLeftX, maxLeftY)
        elif maxLeftX > minRightY:
            # Too far on the right side for partitionX, move left
            imax = i - 1
        else:
            # Too far on the left side for partitionX, move right
            imin = i + 1

    # If we reach here, the input arrays were not sorted as expected
    raise ValueError("Input arrays are not sorted or invalid.")

def findMedianSortedArrays(nums1, nums2):
    # Ensure nums1 is the smaller array
    if len(nums1) > len(nums2):
        nums1, nums2 = nums2, nums1
    m, n = len(nums1), len(nums2)
    low, high = 0, m
    total = m + n
    while low <= high:
        i = (low + high) // 2
        j = (total + 1) // 2 - i
        
        max_left_A = nums1[i-1] if i > 0 else float('-inf')
        min_right_A = nums1[i] if i < m else float('inf')
        max_left_B = nums2[j-1] if j > 0 else float('-inf')
        min_right_B = nums2[j] if j < n else float('inf')
        
        if max_left_A <= min_right_B and max_left_B <= min_right_A:
            if total % 2 == 1:
                return max(max_left_A, max_left_B)
            else:
                return (max(max_left_A, max_left_B) + min(min_right_A, min_right_B)) / 2.0
        elif max_left_A > min_right_B:
            high = i - 1
        else:
            low = i + 1
    return 0.0  # This return is a fallback and should theoretically never be reached

o1-preview output

Deepseek R1 output

from django.db import transaction
from django.db.models import F, Sum

def form_valid(self, form):
    user = self.request.user
    # Extract form data
    data = {field: form.cleaned_data[field] for field in ('email', 'tel', 'country', 'city', 'street')}
    
    # Fetch basket items with related products in a single query
    basket_items = Basket.objects.filter(user=user).select_related('product')
    
    # Calculate total price in the database
    total_price = basket_items.aggregate(
        total_price=Sum(F('product__price') * F('quantity'))
    )['total_price'] or 0  # Handle None total_price
    
    with transaction.atomic():
        # Create the purchase record
        purchase = Purchase.objects.create(
            user=user,
            total_price=total_price,
            **data
        )
        # Add products to the purchase
        purchase.products.add(*[item.product for item in basket_items])
        # Clear the user's basket
        basket_items.delete()
    
    return redirect('history_purchases')

from django.db import transaction
from django.db.models import Sum, F
from django.shortcuts import redirect

def form_valid(self, form):
    user = self.request.user
    with transaction.atomic():
        # Get the user's basket items in a single queryset
        user_baskets = Basket.objects.filter(user=user)
        
        # Extract product IDs and calculate total price using the same queryset
        products = user_baskets.values_list('product', flat=True)
        total_price = user_baskets.aggregate(
            total_price=Sum(F('product__price') * F('quantity'))
        )['total_price'] or 0  # Default to 0 if no items to avoid None
        
        # Create the Purchase instance with form data
        purchase = Purchase.objects.create(
            user=user,
            total_price=total_price,
            **{field: form.cleaned_data[field] for field in [
                'email', 'tel', 'country', 'city', 'street'
            ]}
        )
        
        # Add products and clear the basket
        purchase.products.add(*products)
        user_baskets.delete()
    
    return redirect('history_purchases')

o1-preview output

Deepseek R1 output